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<b>In the given figure, AD=CD and AB=CB....

In the given figure, `AD=CD and AB=CB.` (i) state the three pairs of equal in `Delta ABD and DeltaCBD.` (iii) Is `DeltaABD [-=~?] DeltaCBD` ? Why or why not ? (iii) Does `BD` bisect ? `ABC` ? Given reasons

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`(i)` In `/_\ABD` and `/_\CBD`, the three pairs of equal parts are as given below:
`AB = CB` (Given)
`AD = CD` (Given) and `BD = BD` (Common in both)
`(ii)` From `(i)` above, `/_\ABD cong /_\CBD` (By `SSS` congruence rule)
`(iii) /_ABD = /_CBD` (Corresponding parts of congruent triangles) So, `BD` bisects `/_ABC`.
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