In the adjoining figure if `DE||BC`, then `(AB)/(BD)=(AC)/(CE)`.

In the given figure if DE||BC then prove that (AB)/(DB)=(AC)/(EC)and(AD)/(AB)=(AE)/(AC)

In the adjoining figure if DE||BC , then the value of x is

In the adjoining figure, DE || BC . Prove that area (Delta ACD) = " area " (Delta ABE)

In the adjoining figure, DE||BC and AD=1 cm,BD=2 cm.What is the ratio of the area of triangleABC to the area of triangleADE ?

In the adjoining figure DE||BC and if AD : BD=3 : 5 , then find (are of DeltaADE ) : (area DeltaCDE ).

The straight line parallel to the side BC of DeltaABC intersects the sides AB and AC at the points D and E respectively. Then (AB)/(BD)=(AC)/(CE) .

In the adjoining figure, AB=EF, BC=DE, angleABC=angleFED=90^(@) , prove that AD = CF .

In the adjoining figure, AB=EF, BC=DE, angleABC=angleFED=90^(@) , prove that AD = CF .

Find the value of x, in the adjoining figure, if DE||BC.