`PA^2-PB^2 = a` constant quantity `=2k^2`.

If A and B be the points (3, 4, 5) and (-1,3, -7), respectively, find the equation of the set of points P such that PA^2 + PB^2 = k^2 , where k is a constant.

A and B are fixed points of |PA-PB|=K (constant) and KltAB then the locus of P is

The coordinates of the point A and B are (a,0) and (-a,0), respectively.If a point P moves so that PA^(2)-PB^(2)=2k^(2), when k is constant,then find the equation to the locus of the point P.

If A and B are the points (3,4,5) and (-1,3,-7) respectively, find the equation of the set of points P such that PA^2+PB^2=k^2 where k is a constant.

If A and B be the points (3,4,5) and (-1,3,-7) respectively find the equation of set of ponts P such that PA^2+PB^2=k^2, where k is a constant.

A and B are fixed points of PA+PB=K constant) and KgtAB then the locus of P is

A : If A(4, 0), B ( - 4, 0) are two points and PA- PB = 4 then the locus of P is 3x ^ 2 - y ^ 2 = 12 R : Let A, B be two points. If PA- PB = constant k ( lt AB) then locus of P is hyperbola

If A and B be the points (3,4,5) and (-1,3,-7) , respectively, find the equation of the set of points P such that PA^(2)+PB^(2)=k^(2) , where k is a constant.