The polar of the line 8x-2y=11 with respect to the circle `2x^(2)+2y^(2)=11` is

Find the equation of polar of the point (i) (3,-1) with resect to the cirlce 2x^(2)+2y^(2)=11 (ii) (2,3) with respect to the circle x^(2)+y^(2)+6x+8y-96=0 (iii) (4,3) with respect to the circle x^(2)+y^(2)-8x-6y-9=0 (iv) (1,2) with respect to the cirlce x^(2)+y^(2)=7 (v) (1,-2) with respect to the circle x^(2)+y^(2)-10x-10y+25=0

Find the equation of polar of the point (i) (3,-1) with resect to the cirlce 2x^(2)+2y^(2)=11 (ii) (2,3) with respect to the circle x^(2)+y^(2)+6x+8y-96=0 (iii) (4,3) with respect to the circle x^(2)+y^(2)-8x-6y-9=0 (iv) (1,2) with respect to the cirlce x^(2)+y^(2)=7 (v) (1,-2) with respect to the circle x^(2)+y^(2)-10x-10y+25=0

The pole of a straight line with respect to the circle x^(2)+y^(2)=a^(2) lies on the circle x^(2)+y^(2)=9a^(2) . If the straight line touches the circle x^(2)+y^(2)=r^(2) , then

Position of the point (1,1) with respect to the circle x^(2)+y^(2)-x+y-1=0 is

The pole of a straight line with respect to the circle x^2+y^2=a^2 lies on the circle x^2+y^2=9a^2 . If the straight line touches the circle x^2+y^2=r^2 , then :

Find the equation of the polar of (2, 3) with respect to the circle x^(2) +y^(2) + 6x + 8y -96 = 0