If ` ( 2x )/(3) - ( y )/(2) + (1)/(6)= 0 and (x)/(2) + ( 2y )/(3) = 3` then

If (2x + y + 2)/(5) = ( 3x - y + 1)/( 3 ) = ( 2 x + 2y + 1 )/(6) then

Find the values of x&y when (2x)/(3)+(y)/(2)=3 and (x)/(2)-(2y)/(3)=(1)/(6)

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

x ^ (2) + y ^ (2) + 1, x ^ (2) + 2y ^ (2) + 3, x ^ (2) + 3y ^ (2) + 4y ^ (2) + 2,2y ^ (2) + 6.3y ^ (2) + 8y ^ (2) + 1.2y ^ (2) + 3.3y ^ (2) +4] |

Solve the following simultaneous equations. (2)/(x) + (2)/(3y) = (1)/(6) , (3)/(x) + (2)/(y) = 0

Solve for x and y (2)/(x)+(2)/(3y)=(1)/(6),(3)/(x)+(2)/(y)=0

2x-3y-3=0; (2x)/(3)+4y+(1)/(2)=0

The equation of the circle which cuts orthogonally the three circles x^(2) + y^(2) + 4x + 2y + 1 = 0 , 2x^(2) + 2y^(2) + 8x + 6y - 3 = 0 , x^(2) + y^(2) + 6x - 2y - 3 = 0 is