Angular acceleration of a body of mass 50 kg under the action of a torque of magnitude 500 Nm is 25 `rad//s^(2)`. Then radius of gyration of the body about its axis of rotation is nearly equal to

Angular acceleration of a body of mass 50 kg under the action of a torque of magnitude 500 Nm is 25 rad s^2 . Find the radius of gyration of the body about its axis of rotation.

A torque of magnitude 500 Nm acts on a body of mass 16 kg and produces and angular acceleration of "20 rad/s"^(2) . The radius of gyration of the body is

A toraue of magnitude 4000 N-m, acts on a body of mass 2 kg. If the angular acceleration produced in the body is "20 rad/s"^(2) , then the radius of gyration of the body is

A body of mass M is rotating about an axis with angular velocity omega . If k is radius of gyration of the body about the given axis, its angular momentum is

If the kinetic energy of rotation of a body about an axis is 9 J and the moment of inertia is 2" kg m"^(2) , then the angular velocity of the body about the axis of rotation in rad/s is

Statement-1 : Radius of gyration of a body is a constant quantity. Statement-2 : The radius of gyration of a body about an axis of rotation may be defined as the root mean square distance of the particles of the body from the axis of rotation.

A torque of 400 Nm acting on a body of mass 40 kg produces an angular acceleration of 20 rad/s^2 . Calculate the moment of inertia and radius of gyration of the body.