The magnitude of earth magnetic field at magnetic equator is `2.8 xx 10^(-5) T` . Find magnitude of earth's magnetic field near geomagnetic poles .

A magnetic needle is free to rotate in a vertical plans parallel to the magnetic meridian has its north tip down at 60^(@) with horizontal . The horizontal component of the earth's magnetic field at the place is known to be 0.4 xx 10^(-4) T determine the magnitude of earth's magnetic field at the place.

If the Earth's magnetic field at the equator is about 4 xx 10^(-5)T , What is its approximate magnetic dipole moment ?

The earth's magnetic field at geomagnetic poles has a magnitude 8xx10^(-5)T . Find the magnitude and the direction of the field at a point on the earth's surface where the radius makes an angle of 120^(@) with its axis of the earth's assumed magnetic dipole. What is the inclination dip at this point?

The earth's magnetic field at geomagnetic poles has a magnitude 8xx10^(-5)T . Find the magnitude and the direction of the field at a point on the earth's surface where the radius makes an angle of 120^(@) with its axis of the earth's assumed magnetic dipole. What is the inclination dip at this point?

The total intensity of the earths magnetic field at the magnetic equator is 5 units. Its value at the poles is

Angle of dip at a place is 30^(@) . If the vertical component of earth's magnetic field at that point is 7.5 xx 10^(-5) T, then the total magnetic field of earth at the point will be .

Angle of dip at a place is 30^(@) . If the vertical component of earth's magnetic field at that point is 7.5 xx 10^(-5) T, then the total magnetic field of earth at the point will be .

If the horizontal component of earth's magnetic field at this place is 3 xx 10^(-5) T, calculate the earth's total magnetic field at that place. Angle of dip = delta= 60^(@)