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y=e^(x)+1quad :quad y''-y'=0...

y=e^(x)+1quad :quad y''-y'=0

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Verify that the given functions(explicit or implicit) is a solution of the corresponding differential equation : 1. y = e^(x) + 1 : y'' - y' = 0

In each of the Exercises 1 to 10 vrify that the given functions(explicit or implicit) is a solution of the corresponding differential equation : 1. y = e^(x) + 1 : y'' - y' = 0

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y = e^x + 1 : y'' - y' = 0

Verify that the given function (explicit or implicit) isa solution of the correseponding differential equation : y = e^x + 1 : y'' - y' = 0

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Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: (1)y = e^x +1: y"-y=0(2) y=x^2+2x+C : yprime-2x-2=0 (3) y=cos x+c : y'+sinx=0

(dy)/(dx) -y =e^(x ) " when" x=0 and y=1