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The dissolution of ammonia gas in water ...

The dissolution of ammonia gas in water does not obey Henry's law. On dissolving. a major portion of ammonia molecules unite with `H_(2),O` to form `NH_(4),OH` molecules. A portion of the latter again dissociates into `NH_(4)^(+)`, and `OH^(-)` ions. In solution thercfore, we have `NH_(3)`, molecules, `NH_(4),OH` molecules and `NH_(4)^(+)`, ions and the following equilibrium exist:
`NH_(3(g))` (pressure P and concentration c) `rarr NH_(3(l)) + H_(2),Orarr NH_(4),OH rarr NH_(4)^(+) rarr,+OH^(-)`
Let `c_(1)`,mol/L of `NH_(3)`, pass in liquid state which on dissolution in water forms `c_(2)` mol/ L of `NH_(4),OH.` The solution contains `c_(3)`mol/L of `NH_(4)^(+)`, ions.
Total concentration of ammonia, which can be determined by volumetric analysis is equal to:

A

`c_(1)`

B

`C_(1)+C_(2)+C_(3)`

C

`C_(1)+C_(3)`

D

`C_(2)-C_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
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