Home
Class 12
CHEMISTRY
{:("List-I"," ""List-II"),(1("In" H(3)PO...

`{:("List-I"," ""List-II"),(1("In" H_(3)PO_(4)"solution"),(C=[H_(3)PO_(4)])),((A)[H^(+)],P.sqrt(K_(1)C)),((B)[H_(2)PO_(4)^(-)],Q.K_(2)),((C)[HPO_(4)^(-2)],R.sqrt(K_(1)K_(2))),((D)[PO_(4)^(-3)],S.(K_(2)K_(3))/(sqrt(K_(1).C))):}`

Text Solution

Verified by Experts

The correct Answer is:
A-P;B-P;C-Q,D-S
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILLIBRIUM

    AAKASH SERIES|Exercise LECTURE SHEET ( EXERCISE-II ) (Straight Objective Type Questions)|28 Videos

  • IONIC EQUILLIBRIUM

    AAKASH SERIES|Exercise LECTURE SHEET ( EXERCISE-III) ( Straight Objective Type Questions)|33 Videos

  • GROUP 17 ELEMENTS

    AAKASH SERIES|Exercise EXERCISE - 3.2|38 Videos

  • METALLURGY

    AAKASH SERIES|Exercise EXERCISE - 7.2|23 Videos

Similar Questions

Explore conceptually related problems

{:("List -I Salt","List -II Kg"),((A) AgCI,P.27S^(4)),((B)PbI_(2),Q.108(S)^(5)),((C )AS_(2)S_(3),R.4S^(3)),((D)Ag_(3)PO_(4),S.S^(2)):}

For H_(3)PO_(4+) H_(3)PO_(4) rarr H_(2)PO_(4)^(-)+H^(+)(K_(1))H_(2)PO_(4) rarr HPO_(4)^(-)+H^(+) (K), HPO_(4)^(2) rarr PO_(4)^(3-) + H^(+) (K_(3)) then

{:("List-I"," ""List-II"),(""," ""In the aqueous medium the ion can be"),((A)HPO_(4)^(-2),P."Arrhenius acid"),((B)CO_(3)^(-2),Q."Bronstead base"),((C)H_(2)PO_(3)^(-1),R."Amphoteric"),((D) H_(2)PO_(2)^(-1),S."Bronstead acid"):}

The total no. of diprotic acids among the following is H_(3)PO_(4), H_(2)SO_(4), H_(3)PO_(3), H_(2)S_(2)O_(7), H_(3)BO_(3), H_(3)PO_(2), H_(2)CrO_(4), H_(2)SO_(3), H_(2)CO_(3)

{:("LIST - 1","LIST - 2"),("A) "4NH_(3)+5O_(2)rarr,"1) "PbO+NO_(2)+O_(2)),("B) "P_(4)+3NaOH+3H_(2)Orarr,"2) "N_(2)O+H_(2)O),("C) "NH_(4)NO_(3)rarr,"3) "N_(2)O_(5)+H_(2)O),("D) "Pb(NO_(c))_(2)overset(Delta)rarr,"4) "4NO+6H_(2)O),(,"5) "3NaH_(2)PO_(2)+PH_(3)):} The correct match is

{:("Oxy acid","Basicity"),("A) "H_(3)PO_(2),"1) Tribasic"),("B) "H_(3)PO_(3),"2) Mono basic"),("C) "H_(3)PO_(4),"3) Tetrabasic"),("D) "H_(4)P_(2)O_(6),"4) Dibasic"):} The correct match is

{:("List - I","List - II "),("(Salt)",(k_(1) = 10^(-2) k_(2) = 10^(-7))),((A) NaHSO_(3),(P)"Acidic solution "),((B) Na_(2)HPO_(3),(Q)"lkaline solution "),((C) NAH_(2)PO_(3),(R)"pH independent on concentration "),((D) Al(NO_(3))_(3),(S) "Amphoteric salt "):}

What is the basicity of H_(3)PO_(4) ?

Sec h^(-1)((2)/(3))=log_(e)[((k+1)+sqrt(k^(2)+1))/(k)] then k=