A piece of wood from an aechaeological s...

A piece of wood from an aechaeological sample has 5.0 counts `"min"^(-1)` per gram of C - 14, while a fresh sample of wood has a count of `15.0 "min"^(-1)`. If half-life of C-14 is 5770 years, the age of the archaeological sample is

8,500 years

9,200 years

10,000 years

11,000 years

Text Solution

Verified by Experts

The correct Answer is:

Radioactive decay follows first order kinetics.
Now, `t_(1//2) = 5770` years
`lambda = (0.693)/(t_(1//2)) = (0.693)/(5770) "years"^(-1)`
where , `lambda` = decay constant
If age is t years, then
`t = (2.303)/(lambda) log_(10) ("activity of the fresh sample")/("activity of archaecological sample")`
`implies t = 2.303 xx (5770)/(0.693) xx log_(10) 15/5`
`implies t = 9149` years `~~ 9200` years (approx).

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An archeological sample of wood has half C^(14) activity as compared to that found in fresh wood of the same plant. The half life of C^(14) is 5770 years. The age of archiological sample of wood will be

5770 years

2885 years

11,540 years

1445 years

The activity of carbon-14 in a piece of ancient wood is only 12.5 % . If the half life period of carbon-14 is 5760 years, the age of the piece of wood will be

`17.281 xx 10^(2)` years

`172.81 xx 10^(2)` years

`1.7281 xx 10^(2)` years

`1728.1 xx 10^(2)` years

The activity of carbon -14 in a piece of an ancient wood is only 12.5 %. If the half-life period of carbon -14 is 5760 years, the age of the piece of wood will be (log 2 = 0.3010)