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Al^(3+) has a lower radius than Mg^(2+) ...

`Al^(3+)` has a lower radius than `Mg^(2+)` ion because

A

Mg atom has less number of neutron than Al

B

`Al^(3+)` has higher nuclear charge than `Mg^(2+)`

C

their electronegatives are different

D

Al has a lower ionization potential than Mg atom.

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Verified by Experts

The correct Answer is:
B

`Al^(3+)` has a higher nuclear charge `(+13)` than `Mg^(2+) (+12)`.
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