[K_(b)" for "CH_(2)ClCOO^(-)" is "6.4times10^(-12)." The "],[pH" of "0.1MCH_(2)ClCOONa" in water is : "]

K_(b)" for "CH_(2)ClCOO^(-) is 6.4xx10^(-12). The pH of "0.1 M "CH_(2)ClCOO^(-) in water is :

K_(b)" for "CH_(2)ClCOO^(-) is 6.4xx10^(-12). The pH of "0.1 M "CH_(2)ClCOO^(-) in water is :

Dissociation constant of CH_2 CICOOH in water is 1.35 xx10^(-3) . What is the pH of (a) 0.1M CH_2 CICOOH and (b) 0.1M CH_2 CICOOK ?

Calculate the pH of 0.2 M CH_3 COOH (K_a = 1.5 xx 10^-5) .

If K_(a) of HCN =4xx10^(-10) , then the pH of 2.4 xx 10^(-1) molar HCN(aq) is

Calculate the pH of a solution of given mixture. a. (2g CH_(3)COOH +3g CH_(3) COONa) in 100mL of mixture. b. 5mL of 0.1M NH_(4)OH + 250mL of 0.1 M NH_(4)C1 . c. (0.25 "mol of" CH_(3)COOH + 0.35 "mol of" CH_(3) COONa) in 500mL mixture. K_(a) "of" CH_(3)COOH = 1.8 xx 10^(-5) (pK_(a) = 4.7447) K_(b) "of" NH_(4)OH = 1.8 xx 10^(-5) (pK_(b) = 4.7447)

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)