Prove that `mu = (1)/(sin C)`' where `C` is the critical angle.

For a ray of light travelling from a denser medium of refractive index mu_1 to a rarer medium of refractive index mu_2 ,prove that (mu_2)/(mu_1) = sin C , where C is the critical angle of incidence for the media.

Prove that mu=1/sinC where C is the critical angle?

The velocity of light through media 'A' and 'B' are V and 2V, respectively. The value of sin C is ______ [where 'C' is the critical angle].

Correct the following sentences if required: mu = sin C where mu = refractive index, C = critical angle

A ray of light passes from glass (mu_(g) = 1.52) to water (mu_(w) = 1.33) . What is the critical angle of incidence?

A ray of light passes from glass ( mu = 1.5) to water ( mu = 1.33). The value of the critical angle of glass is ..........

Critical angle of glass is theta_(1) and that of water is theta_(2) . The critical angle for water and glass surface would be (mu_(g) = 3//2,mu_(w) = 4//3)

Critical angle of glass is theta_(1) and that of water is theta_(2) . The critical angle for water and glass surface would be (mu_(g)=3//2, mu_(w)=4//3)