The work done is breaking a water drop of radius 1 cm into 64 equal droplets
(Surface tension of water is 0.07 N/m)

Surface tension changes with temperature. Calculate the work done in breaking water drop of radius 1 mm to 1000 droplets. Surface tension of water = 72 x 10^(-3) N/m .

A water drop of radius 1 cm is broken into 1000 equal droplets. If the surface tension of water is 0.075 N/m , then the gain in surface enrgy will be

A water drop of radius 1 cm is broken into 1000 equal droplets. If the surface tension of water is 0.075 N/m , then the gain in surface enrgy will be

Calculate the work done in breaking a mercury drop of radius 1mm into one thousand droplets of the same size. Surface tension of mercury is 525 xx 10^-3 N//m .

The diameter of one drop of water is 0.2 cm. The work done in breaking one drop into 1000 equal droplets will be :- (surface tension of water =7xx10^(-2)N//m )

Work done is splitting a drop of water of 1 mm radius into 64 droplets is (surface tension of water =72xx10^(-3)j m^(2))

Calculate the work done when a water drop of diameter 2mm is split into 10^(9) identical water droplets. Surface tension of water is 7.4xx10^(-2)Nm^(-1) .

Work done in splitting a drop of water of 1 mm radius into 10^6 droplets is (Surface tension of water= 72xx10^(-3)J//m^(2) )