An iron block of mass `2kg`, fall form a height `10m`. After colliding with the ground it loses `25%` enegry to surroundings. Then find the temperature rise of block. (Take sp. Heat of iron `470 J//kg^(@)C)`

A body of mass 0.2 kg falls from a height of 10 m to a height of 6 m above the ground. Find the loss in potential energy taking place in the body. [g=10ms^(-2)]

Calculate the amount of heat required to raise the temperature of 800 g of iron from 40^(@)C to 240^(@)C . Sp. heat capacity of iron 440J//kg^(@)C .

(Take C_(w)=4180 J kg^(-1) K^(-1)) A block of weight 5kg falls from a height of 5m into a bucket containing 10L of water. If all the mechanical energy of the block is used to heat water, find the rise in temperature of water. Take g= 10ms^(-2)

A 15kW drilling machine is used to drill a bore in a small aluminium block of mass 10 kg. Assuming 50% power is used up in heating the machine itself or lost to the surroundings then, the rise in temperature of the block in 2 minutes is (Specific heat capacity of aluminium =0.91 J g^-1^@C^-1 )

A ball falls under gravity from a height of 10m with an initial velocity. It collides with the ground,loses 50% of its engery and then rises to the same height.Find the initial velocity.

A brass sphere of mass 0.2 kg falls freely from a height of 24m and bounces to a height of 8m from the ground. If the dissipated energy in this process is dosorbed by the sphere the rise in its temperature is (specific heat of brass =360 J " kg"^(-1)k^(-1) and g=10ms^(-2) ).

A ball falls under gravity from a height of 10m with an initial downward velocity u. It collides with the ground, loses 50% of its energy in collision and then rises back to the same height. Find the initial velocity ''u''.