In the nuclear reaction : `X (n, alpha)_3 Li^7` the term `X` will be `3`

In the nuclear reaction X(n, alpha)_3 Li^7 , identify X.

In the nuclear reaction ._7^14N + X to ._6^14C + ._1^1H the X will be

In the nuclear reaction ._85 X^297 rarr Y + 4 alpha, Y is.

In compound X(n, alpha) rarr ._(3)Li^(7) , the element X is

In compound X(n, alpha) rarr ._(3)Li^(7) , the element X is

Calculate the energy released in the nuclear reaction "_3 ^7 Li+p rarr 2 alpha given mass of "_3 ^7 Li atom and of helium atom to be 7.016u and 4.0026u respectively.

Calculate the energy released in the nuclear reaction "_3^7 Li + P rarr 2alpha given mass of "_3^7Li atom and helium atom are 7.016u and 4.0026u respectively.