" 32."8x^(2)+2xy-15y^(2)

If one of the lines 2x^(2)-xy-15y^(2)=0 is perpendicular to line kx+y=0 then k=

The combined equation of the line passing through origin and perpendicular to 2x^(2)-7xy-15y^(2)=0 is

The combined equation of the line passing through origin and perpendicular to 2x^(2)-7xy-15y^(2)=0 is

Find the real numbers (x,y) that satisfy the equation: xy^(2) = 15x^(2) +17xy + 15y^(2) x^(2)y = 20x^(2) + 3y^(2)

Add: 8x^(2) - 5xy - 3y^(2), 2xy - 6y^(2) + 3x^(2) and y^(2) + xy - 6x^(2)

Evaluate : 3x^(2) + 5xy - 4y^(2) + x^(2) - 8xy - 5y^(2)

Add 2x^(2)+5xy-2y^(2), 3x^(2)-2xy+5y^(2) and 2x^(2)+8xy+3y^(2)

Divide 14x^(3)y^(2)+8x^(2)y^(3)-32x^(2)y^(5) by -2xy^(2)

The figure formed by the pairs of lines 2x^(2)+3xy-2y^(2)=0 and 2x^(2)+3xy-2y^(2)-5x+15y-25=0 is a