सिद्ध करें की `cot(A+B)cot(A-B)=(cos^2A-sin^2 B)/(sin^2A-sin^2B)`

Show that cot(A+B)cot(A-B)=(cos^2A-sin^2B)/(sin^2A-sin^2B)

Prove that :(tan(A+B))/("cot"(A-B))=(sin^2A-sin^2B)/(cos^2A-sin^2B)

Prove that :(tan(A+B))/(cot(A-B))=(sin^(2)A-sin^(2)B)/(cos^(2)A-sin^(2)B)

Prove that (tan(A+B))/(cot(A-B))=(sin^(2) A-sin^(2)B)/(cos^(2)A-sin^(2)B) (when the denominators on both sides are non-zero)

sin^(2)A cos^(2)B-cos^(2)A sin^(2)B=sin^(2)A-sin^(2)B

Prove that : cot^(2) A - cot^(2) B = (cos^(2) A - cos^(2) B)/ (sin^(2) A sin^(2) B) = cosec^(2) A - cosec^(2)B

cos(A+B)*cos(A-B)= (a) sin^2A-cos^2B (b) cos^2A-sin^2B (c) sin^2A-sin^2B (d) cos^2A-cos^2B

Prove that sin(A+B)sin(A-B)=cos^2B-cos^2A

cot A cot B=2,cos(A+B)=(3)/(5)rArr sin A sin B=

cot A+cot B+cot C+(cos(A+B+C))/(sin A sin B sin C)=