What is the minimum phase difference between two simple harmonic oscillations given by `y_(1)=(1)/(2) "sin" omega t+(sqrt(3))/(2) "cos" omega t`
`y_(2)= "sin" omega t+ "cos" omega t` ?

What is the minimum phase difference between two S.H.M.s given by x_(2)= "sin" omega t + "cos" omegat t " and " x_(1)=(1)/(2) "sin" omega t + (sqrt(3))/(2) "cos" omega t

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Find the resultant amplitude of the following simple harmonic equations : x_(1) = 5sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t

The equation of displacement of a harmonic oscillator is x = 3sin omega t +4 cos omega t amplitude is

The resultant amplitude due to superposition of three simple harmonic motions x_(1) = 3sin omega t , x_(2) = 5sin (omega t + 37^(@)) and x_(3) = - 15cos omega t is

The resultant amplitude due to superposition of three simple harmonic motions x_(1) = 3sin omega t , x_(2) = 5sin (omega t + 37^(@)) and x_(3) = - 15cos omega t is

Identify which of the following function represent simple harmonic motion. (i) Y = Ae^(I omega t) (ii) Y = a e^(- omega t) (iii) y = a sin^(2) omega t (iv) y = a sin omega t + b cos omega t (v) y = sin omega t + b cos 2 omega t

Identify which of the following function represent simple harmonic motion. (i) Y = Ae^(I omega t) (ii) Y = a e^(- omega t) (iii) y = a sin^(2) omega t (iv) y = a sin omega t + b cos omega t (v) y = sin omega t + b cos 2 omega t

Wave equations of two particles are given by y_(1)=a sin (omega t -kx), y_(2)=a sin (kx + omega t) , then