If in a projection motion, the maximum height is equal to a horizontal range, find the angles of projection `[tan^(-1) (4) = 76^(@)]`

During a projectile motion if the maximum height equal the horizontal range, then the angle of projection with the horizontal is :

During a projectile motion if the maximum height equals the horizontal range,then the angle of projection with the horizontal is :

A projectile is projected from ground such that the maximum height attained by, it is equal to half the horizontal range.The angle of projection with horizontal would be

A projectile is projected from ground such that the maximum height attained by, it is equal to half the horizontal range.The angle of projection with horizontal would be

The horizontal range is four times the maximum height attained by a projectile . The angle of projection is

A body is thrown at an angle alpha to the horizontal with initial velocity v_0 .Assuming air drag to be negligible , find (i)the time of motion, (ii)maximum height of ascent and the horizontal range, (iii)the angle of projection at which they are equal , (iv)the angle of projection at which the horizontal range is maximum and the angle at which the vertical range is maximum.

If the horizontal range is 4 times of the maximum height then what is the angle of projection?