`7(1)/(8)-6(1)/(10)`

Simplify (9.6xx3.6+7.2+10.8" of "(1)/(18)-(1)/(10))

(7)/(8)-(1)/(6)

The sum to infinity of the series (1)/(2.4)+(1)/(4.6)+(1)/(6.8)+(1)/(8.10)+...... is

Find the mode in each of the following data collection. 8,6,7,6,5,4, (1)/(2), 7 (1)/(2), 6 (1)/(2), 8 (1)/(2), 10,7,5,5(1)/(2), 8,9 7,5,6,8 (1)/(2),6

If(1)/(6!)+(1)/(7!)=(X)/(8!), thenx =

Evaluate 8-8xx(2(1)/(5)-1(2)/(7))/(2-(1)/(6-(1)/(6)))

1(1)/(8)+1(6)/(7)+3(3)/(5)=?

1(1)/(8)+1(6)/(7)+3(3)/(5)=?

18-((1)/(8)){11+16-(10+7-bar(6+8)}=