If 2, 7, 9 and 5 are subtraced respectively from four numbers in geometric progression, then the resulting numbers are in arithmetic progression. The smallest of the four numbers is

Suppose 2,7,9,5 are subtracted respectively from first,second,third, fourth terms of a G.P consisting of four numbers,the resulting numbers are found to be in A.P,then smallest of the four numbers in the G.P is 1) -24,2) 0 3) 6 4) 3

If a, b and c are three positive numbers in an arithmetic progression, then:

Seven integers A, B, C, D, E, F and G are to be arranged in an increasing order such that I. First four numbers are in arithmetic progression. II. Last four numbers are in geometric progression III. There exists one number between E and G. IV. There exist no numbers between A and B. V. D is the smallest number and E is the greatest. VI. A/D = G/C = F/A gt 1 VII. E = 960 The position and value of A is

let a < b , if the numbers a , b and 12 form a geometric progression and the numbers a , b and 9 form an arithmetic progression , then (a+b) is equal to:

If every term of a series in geometric progression is multiplied by a real number, then the resulting series also will be in geometric progression. [True/False]

Three numbers are in arithemetic progression whose sum is 33 and product is 792 then the smallest number among these numbers is

Standard results|Some special series| Arithmetic geometric progression