A rod AB is placed on smooth inclined plane as shown in the figure. At the instant which is shown in the figure, the angular velocity of the rod is

A rod of length l slided down along the inclined wall as shown in figure. At the instant shown in figure, the speed of end A is v, then the speed of B will be

Two particles each of mass M are connected by a massless rod. The rod is lying on the smooth horizontal surface. If one of the particle is given an impulse MV as shown in the figure then angular velocity of the system would be:

Two particles each of mass M are connected by a massless rod. The rod is lying on the smooth horizontal surface. If one of the particle is given an impulse MV as shown in the figure then angular velocity of the system would be:

A uniform rod PQ of mass m and length t rotates with an angular velocity a while its center moves with linear velocity v = (2omega* f) / 3 on a smooth horizontal surface If the end Q of the rod is suddenly gets stuck at the moment as shown in the figure then angular velocity of the rod will be

A uniform rod of mass m and length l is pivoted smoothly at point O as shown in figure. If a horizontal force F acts at the bottom of the rod and omega is the angular velocity of the rod which is a function of angle of rotation theta , then the maximum angular displacement of the rod is (Acceleration due to gravity, g)

A block is dragged on a smooth plane with the help of a rope which moves with a velocity v as shown in figure. The horizontal velocity of the block is :

In the figure shown the instantaneous speed of end A of the rod is v to the left the angular velocity of the rod of lengthL must be

A rod AB of length L slides in the XY plane. If the rod makes an angle theta with the vertical, the angular velocity of the rod can be found by an expression which is