The ground state energy of hydrogen atom is `-13.6eV`. If the electron jumps to the ground state from the `3^("rd")` excited state, the wavelength of the emitted photon is

The ground state energy of hydrogen atom is - 13.6eV. The kinetic energy of the electron in this state is:

Ground state energy of hydrogen atom is -13.6 eV . If the electron in this atom jumps from the fourth level to the second level, what will be the wavelength of the emitted radiation ?

The ground state energy of hydrogen atom is -13.6eV. What are P.E. and K.E. of electron in this state?

The ground state energy of hydrogen atom is -13.6eV. When its electron is in the first excited state, its excitation energy is

The ground state energy of hydrogen atom is -13.6 eV . The energy of second excited state of He^(+) ion in eV is

The ground state energy of hydrogen atom is -13.6 eV . The energy of second excited state of He^(+) ion in eV is

The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is:

The energy in the ground state of hydrogen atom is -13.6 eV , then energy of 1st excited state is

The ground state energy of hydrogen atom is -13.6eV. what is the potential energy of the electron in this state?