In `triangleABC, (sinB)/(sin(A+B))` =

In triangleABC, sin((B-C)/(2))=

Statement:1 In triangleABC , if a lt b sinA , then the triangle is possible. And Statement:2 In triangleABC a/(sinA)= b/(sinB)

In triangleABC, a^(2)sin(B-C)=

In triangleABC,sin((B+C)/2) =

In triangleABC, a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=

For any acute angled triangleABC,(sinA)/(A)+(sinB)/(B)+(sinC)/(C ) can