The tangents drawn at end points of latus rectum of parabola S=0 intersect at (1,1) and (3,2) is its focus.Then axis of parabola S=0 is

The ends of latus rectum of parabola x^(2)+8y=0 are

The end points of latus rectum of the parabola x ^(2) =4ay are

Ends of latus-rectum of parabola 3y^(2) = 20 x are

The end points of the latus rectum of the parabola x ^(2) + 5y =0 is

If two ends of latus rectum of a parabola are the points (3,6) and (5,6), then equation of the parabola is

Enda of latus-rectum of parabola 3x^(2) + 8y = 0 are

Statement-1: Point of intersection of the tangents drawn to the parabola x^(2)=4y at (4,4) and (-4,4) lies on the y-axis. Statement-2: Tangents drawn at the extremities of the latus rectum of the parabola x^(2)=4y intersect on the axis of the parabola.

Tangent drawn at point P(1,3) of a parabola intersects its tangent at vertex at M(-1,5) and outs the axis of parabola at T.If R(-5,5) is a point on SP; where S is focus of the parabola,then