The time period of a body executing SHM is 0.05 s. if the amplitude is 4 cm, then what will be the maximum velocity and maximum acceleration of the body?

The time period of a body executing S.H.M. is 0.05 s and the amplitude of vibration is 4 cm. What is the maximum velocity of the body ?

The time period of an oscillating body executing SHM is 0.05 sec and its amplitude is 40 cm. The maximum velocity of particle is :

Time period of a particle executing SHM is T = 1 second and its amplitude of vibration is A = 0.04 m. Determine the maximum velocity and maximum acceleration of the particle.

The particle executes simple harmonic motion have periodic time 0.05s and amplitude 4 cm, then what its maximum velocity?

A particle of mass 0.5g is executing SHM with a time period of 2s and an amplitude of 5 cm. Calculate its (i) maximum velocity, (ii) maximum acceleration and (iii) velocity, acceleration and force acting on the particle when it is at a distance of 4 cm from its position of equilibrium.

A body executing SHM with amplitude of 2 cm makes (30/pi) vibrations in 1 min. What is the maximum velocity of the body during the motion?

The velocity-time graph of a particle executing SHM is as shown in the figure. The amplitude and maximum acceleration of the particle respectively are

A body is executing S.H.M. with an amplitude of 2cm makes 30/pi vibrations per minute. What maximum velocity of the body during the motion ?

A body executing SHM has a maximum velocity of 1ms^(-1) and a maximum acceleration of 4ms^(-1) . Its time period of oscillation is

particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds , then the maximum velocity of the particle will be