Recommended Questions
- Let f(n) = sum(r=1)^n[r^2(.^nCr -^nC(r-1))+(2r+1)^nCr], then f(30) is
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- If f(n) = sum(r=1)^n [r^2(nCr-nC(r-1))+(2r+1)nCr], then f(50) is
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- If f(n) = sum(r=1)^n [r^2(nCr-nC(r-1))+(2r+1)nCr], then f(50) is
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- .(n–r+ 1) * ^nC(r-1) = m*^nCr হলে, m =
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- .^nCr:^nC(r+1):^nC(r+2) = 1:2:3 হলে, n ও r-এর মান নির্ণয় কর।
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- .^nCr = (n-r+1)/r *^nC(r-1)
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- If ""^nCr denotes the number of combinations of n things , taken r at ...
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- sum(r=1)^(10) r. (""^nCr)/(""^nC(r-1)) =
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- sum(r=1)^(n) (-1)^(r-1) ""^nCr(a - r) =
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