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Calculate the amount of energy released ...

Calculate the amount of energy released during the `alpha`-decay of
`._(92)^(238)Urarr_(90)^(234)Th+._(2)^(4)He`
Given: atomic mass of `._(92)^(238)U=238.05079 u`, atomic mass of `._(90)^(234)Th=234.04363 u`,
atomic mass `._(2)^(4)He=4.00260u , 1u=931.5 MeV//c^(2)`. Is this decay spontaneous?Give reason.

Text Solution

Verified by Experts

Given nuclear reaction is `._(92)^(238)U rarr ._(90)^(234)Th + ._(2)^(4)He+Q`
Mass defect `=M_(U)-M_(Th)-M_(He)`
`=238.05079-234.043636-4.002600=0.00456 u`.
Energy released `=(0.00456 u) xx (431.5 MeV//C^(2))=4.25 MeV`.
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