Two point charges, `q_(1)=10xx10^(-8)C` and `q_(2)=-2xx10-8C` are separated by a distance of 60 cm in air.
(i) Find at what distance from the 1st charge, `q_(1)`, would the electric potential be zero.
(ii) Also calculate the electrostatic potential energy of the system.

Explanation

Let's solve the given problem step by step.

### Given:
- \( q_1 = 10 \times 10^{-8} \, \text{C} \)
- \( q_2 = -2 \times 10^{-8} \, \text{C} \)
- Distance between the charges \( d = 60 \, \text{cm} = 0.6 \, \text{m} \)

### Part (i): Finding the distance from \( q_1 \) where the electric potential is zero.
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