For what kinetic energy of a proton, will the associated de-Broglie wavelength be 16.5 nm?

Explanation

To find the kinetic energy of a proton that corresponds to a de-Broglie wavelength of 16.5 nm, we can follow these steps:

### Step 1: Convert the wavelength from nanometers to meters
Given:
\[ \text{Wavelength} (\lambda) = 16.5 \text{ nm} = 16.5 \times 10^{-9} \text{ m} \]

...