The radius of innermost electron orbit of a hydrogen atom is `5.3xx10^(-11)m`. What is the radius of orbit in second excited state?

Explanation

Radius of nth orbit of hydrogen atom `r=n^2xx 5.3xx 10^-11m`
`therefore` Radius of second state ` n=3)` is orbit of hydrogen atom ` r=(3)^2xx5.3xx10 ^-11 m`
`9xx5.3 xx10^-11 m= 4.77 xx10^-11 m`.