An electron is accelerated through a potential difference of 64volts. What is the de-broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?

Explanation

Here,
`therefore` de-Broglie wavelength is `V=64` volts
`lambda =(1.227)/(sqrt(V))nm =(1.227)/(sqrt(64)) =(1.227)/(8)=0.1533 nm`.
This wavelength is associated with X-rays (range :1 nm `10 ^-3` nm)