Fig, shows two indentical capacitors `C_(1) and C_(2)` each of `1 muF` capacitance connected to a battery of 6V. Inditally, swich S is closed. After some time, the swich S is left open and dielectric slabs of K = 3 are inserted to filll completely the space between the plates of two capacitors . How will (i) the charge and (ii) potential difference between the plates of the capacitors be affected after the slabs are inserted ?

Explanation

When switch S is opened and dielectric is introduced then capacity of each capacitor `C'=KC=3xx1xx10^(-6)F`
`=3xx10^(-6)F`
So, charge on `C_1`.
`E_1=3CV=3xx10^(-6)xx6=18xx10^(-6)C`
Charge on eah capacitor will become 3 time.
Potenial difference on `C_1` will remain same i.e., 6V.
`:. " potential difference of "C_2 "will be, "V_1=Q/(3C)=V/3=6/3=2V`.