In the circuit shown, `R_1=4Omega,R_2=R_3=15Omega,R_4=30OmegaandE=10V`. Caculate the equivalent resistance of te circuit and the current in each resistor.

Explanation

`R_3 and R-4` are in parallel combination.

`1/R_34=1/R_3+1/R_4=1/15+1/30`
`=(2+1)/30=1/10=1/100rArrR_34=10Omega`.
`R_34and R_2` are in parallel combination.
`1/R_234=1/_34+1/R_2=1/10+1/15=(15+10)/150=25/150=1/6`
`R-234=6Omega`. ltbr. `R_1234=R_234+R_1=6+4`
`R_1234=10Omega`
`IV/R=10/10rArrI=1A`.