A rectangular conductor LMNO is place in a uniform magnetic field of 0.5 T Fig. The field is directed perpendicular to the plane to the conductor. When the arm MN of length 20 cm is moved with a velocity of 10 `m//s` calculate the emf induced in the arm. Find the value of induced current if resistance of arm MN is 5 Omega

Explanation

Let ON be the x at some instant.
The emf induced in the loop = e.
`e = -(d phi)/(dt)=(-d(Blx))/(dt)`
`e = Bl((-dx)/(dt))=BlV = 0.5 xx 0.2 xx 10 = 1V`
Current in the arm, `I = (e)/(R)=(1)/(5)=0.2A`.