Home
Class 12
PHYSICS
The electon, in a hydrogen atom, is in i...

The electon, in a hydrogen atom, is in its second excited state. Calculate the wavelength of the lines in the Lyman series, that can be emitted through the permisible transitions of this electron.
Given the value of Rydberg constant, `R=1.1xx10^(7)m^(-1))`

Text Solution

Verified by Experts

`(1)/(lamda)=R_(H)((1)/(1^(2))-(1)/(2^(2)))=R_(H)(1-(1)/(4))=(3)/(4)R_(H)`
`implies1=(4)/(3R_(H))=(4)/(3xx1.097xx10^(7))=1.215xx10^(-7)=1215A^(@)`.
Promotional Banner

Topper's Solved these Questions

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SECTIONS-C|13 Videos

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SECTIONS-D|4 Videos

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise C.B.S.E.CLASS-XII PHYSICS (THEORY) [SET-I] (SECTION-A)|5 Videos

  • SAMPLE PAPER 2019

    XII BOARDS PREVIOUS YEAR|Exercise SECTION D|6 Videos

Similar Questions

Explore conceptually related problems

Find the wavelength of H_(alpha) line given the value of Rydberg constant, R=1.1xx10^7m^-1 .

A hydrogen atom is in second excited state. Calculate the maximum possible spectral lines emitted for hydrogen atom to reach its ground state.

Calculate the shortest wavelength of light emitted in the Paschen series of hydrogen spectrum. Which part of the electromagnetic spectrum, does it belong ? ( Given : Rydberg constant , R = 1.1 xx 10^(7)m^(-1)

Calculate the wavelength for the first three lines in Paschen series. (GivenRH = 1.097 xx10^7 m^(-1) )

The Rydberg constant for hydrogen is 1.097xx10^(7)m^(-1) . Calculate the short and long wavelength limits of Lyman series.

A hydrogen atom in its excited state emits radiations of wavelengths 1218 Å and 974.3 Å when it finally comes to the ground state. Identify the energy levels from where transitions occur. Given Rydberg constant R = 1.1 xx 10^7 m^(-1) . Also specify the spectral series to which these lines belong.