A wheel of radius `R=0.1m` is rolling without slipping on a horizontal surface as shown in the firgure. Centre of the wheel moves with a constant speed `sqrt3m//s`. The speed of the point P with respect to ground is

A uniform ring rolls on a horizontal surface with out slipping. Its centre of mass moves with a constant speed v. then speed of the upper most point on its rim above the ground is

A uniform ring rolls on a horizontal surface with out slipping. Its centre of mass moves with constant speed v. Then speed of the upppermost point on its rim above the ground is

A wheel ios rolling without sliding on a horizontal surface. The centre of the wheelk moves with a constant speed v_(0) . Consider a point P on the rim which is at the top at time t=0. The square of speed of point P is plooted against time t. The correct plot is (R is radius of the wheel)

A solid sphere of mass m and radius R rolls without slipping on a horizontal surface such that v_(c.m.)=v_(0) .

A wheel of radius R rolls without slipping on a horizontal ground. The distance travelled by a point on the rim in one complete rotation is:

A ring rolls without slipping on the ground. Its centre C moves with a constant speed u.P is any point on the ring. The speed of P with respect to the ground is v .

A ring rolls without slipping on the ground. Its centre C moves with a constant speed u.P is any point on the ring. The speed of P with respect to the ground is v .

A symmetrical body of mass M and radius R is rolling without slipping on a horizontal surface with linear speed v. Then its angular speed is

A wheel of radius 0.5m is moving with a speed of 12m/s. Find its angular speed ?