Draw a graph showing the variation of de Broglie wavelength of a particle of charge q and mass m with accelerating potential. Proton and deuteron have the same de Broglie wavelengths. Explain which has more kinetic energy.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the relationship between de Broglie wavelength and accelerating potential
The de Broglie wavelength (λ) of a particle is given by the formula:
\[ \lambda = \frac{h}{p} \]
where \( h \) is Planck's constant and \( p \) is the momentum of the particle. For a charged particle accelerated through a potential \( V \), the kinetic energy (KE) gained is given by:
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