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At a place, the horizontal component of ...

At a place, the horizontal component of earth's magnetic field is V and angle of dip is `60^(@)`. What is te value of horizontal component of earth's magnetic field at equator ?

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`B_(H) = B_(c) cos theta, theta = 60^(@) B_(H) = B_(c)` `cos60^(2) = B_(c) xx 1/2 rArr B_(c ) = 2B_(H)`
At equator , `theta= O`.
`rArr B_(c) = B_(H) = 2B`.
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