`4S(s)+60to4SO_(3)(g),DeltaH` f or this reaction is - 1583.2 kJ . The enthalpy of formation of sulphur trioxide is -

4S(s)+60_2to4SO_(3)(g),DeltaH f or this reaction is - 1583.2 kJ . The enthalpy of formation of sulphur trioxide is -

The Delta H^(theta) for the reaction 4S(s) + 6O_(2)(g) rarr 4 SO_(3)(g) is -1583.2kJ . Standard enthalpy of formation of sulphur trioxide is:

When 5 g of sulphur is burnt to SO_(2) , 46 kJ of heat is liberated. What is the enthalpy of formation of sulphur dioxide?

When 0.5 g of sulphur is burnt to SO_(2):4.6 kJ of heat is liberated. What is the enthalpy of formation of sulphur dioxide ?

The DeltaH_r^@ for the reaction 4S(s)+6O_2(g)rarr 4SO_3(g) is -1583.2 KJ calculate Delta H_f^@ of sulphur trioxide.

Consider the reaction : SO_(2)(g)+(1)/(2)O_(2)(g) rarr SO_(3)(g),DeltaH=-98.3kJ If the enthalpy of formationof SO_(3)(g) is -395.4kJ , then the enthalpy of formation of SO_92)(g) is

Delta H for the reaction, SO_(2) (g) + (1)/(2) O_(2)(g) hArr SO_(3)(g) " " Delta H = -98.3kJ If the enthalpy of formation of SO_(3)(g) is -395.4kJ, then enthalpy of formation of SO_(2)(g) is:

Given that (1)/(2)S_(8(s)) + 6O_(2(g)) rarr 4SO_(3(g)), Delta H^(0) = - 1590kJ . The standard enthalpy of formation of SO_(3) is