A(p,1,-1), B(2p,0,2) and C(2+2p,p,p) are three points. Find the value of p such that the vectors AB abd BC are perpendicular.

A(p,1,-1), B (2p,0,2) and C(2+2p,p,p) are three points . Find the value of p so that the vectors vec(AB) and vec(BC) are perpendicular to each other .

If p+1/p=2 then the value of p^2-1/p^2 is :

If A(1,p^(2)),B(0,1) and C(p,0) are the coordinates of three points then area of the triangle ABC is 1/(lamda)|p^(3)-p+1| . The value of lamda is

If A(1,p^(2)),B(0,1) and C(p,0) are the coordinates of three points then area of the triangle ABC is 1/(lamda)|p^(3)-p+1| . The value of lamda is

If P(A)=2/3,P(B)=1/2 and P(AnnB)=1/6 then find the value of P(AnnB^C) .

If p, 2p - 1, 2p + 1 are three consecutive terms of an A.P., then what is the value of p ?

If (2p)/(p^(2)-2p+1)=(1)/(4),p!=0, then the value of p+(1)/(p)