The force constant of an ideal spring is 200 newton per meter. It is loaded with a mass of `200//pi^(2)` kg at the lower end the time period of its vibration is

A flat spiral spring of force constant K is loaded with mass M and oscillates vertically with a time period T. Then the mass suspended to the free end is

A mass of 0.1 kg hangs at the end of a spring. When a mass of 0.01 kg more is added at the end of the spring, it stretches by 5 cm more. When the extra 0.01 kg mass is removed, determine the time period of vibration of the system.

A body of mass m attached to one end of an ideal spring of force constant k is executing simple harmonic motion. Establish that the time - period of oscillation is T=2pisqrt(m//k) .

A flat spiral spring of force constant k is loaded with mass M and oscillate about vertical with a time period T. Then the mass suspended to the free end is

The figure shows the arrangement of three springs of different spring constant, connected to a mass m. When mass m oscillates find equivalent spring constant and the time period of vibration.

A mass m is attached to the free end of a massless spring of spring constant k with its other end fixed to a rigid support as shown in figure. Find out the time period of the mass, if it is displaced slightly by an amount x downward.

When a mass of 4 kg is hung from the lower and of a spring.IF elongates by 1cm.(i) What is the force constant of the spring? (ii) If a load of 2kg is hung from the lower end of the spring , then find its elongation.

The time period of a mass loaded spring is .T.. If 20% of its turns are cut and removed, the same mass is attached to the remaining spring would oscillate with a time period of