If the kinetic energy of a rotating body about an axis is decreased by 36%, its angular momentum about that axis is

If the K.E. of a rotating body about an axis is decreased by 36% , its angular momentum about that axis

The kinetic energy of rotation of a body about a given axis is 157J . Its angular momentum about the same axis is 12.5 kgm^2s^-1 .Find the frequency of rotation of the body and moment of inertia about the given axis?

What is the kinetic energy of a rotating body about its axis of rotation ?

The rotational kinetic energy of a rigid body of moment of inertia 5 kg-m^(2) is 10 joules. The angular momentum about the axis of rotation would be -

If the kinetic energy of rotation of a body about an axis is 9 J and the moment of inertia is 2" kg m"^(2) , then the angular velocity of the body about the axis of rotation in rad/s is

If the angular momentum of a rotating body about an axis is increased by 10%. Its kinetic energy increases by

If the angular momentum of a rotating body about an axis is increased by 10 %. Its kinetic energy increases by

The kinetic energy of an object rotating about a fixed axis with angular momentum L = I omega can be written as.