Prove that the farthest point on the circle,`x^2 + y^2-2x-4y-11=0` from the origins

The nearest point on the circle x^(2)+y^(2)-6x+4y-12=0 from (-5,4) is

The nearest point on the circle x^(2)+y^(2)-6x+4y-12=0 from (-5,4) is

Length of the tangent. Prove that the length t o f the tangent from the point P (x_(1), y(1)) to the circle x^(2) div y^(2) div 2gx div 2fy div c = 0 is given by t=sqrt(x_(1)^(2)+y_(1)^(2)+2gx_(1)+2fy_(1)+c) Hence, find the length of the tangent (i) to the circle x^(2) + y^(2) -2x-3y-1 = 0 from the origin, (2,5) (ii) to the circle x^(2)+y^(2)-6x+18y+4=-0 from the origin (iii) to the circle 3x^(2) + 3y^(2)- 7x - 6y = 12 from the point (6, -7) (iv) to the circle x^(2) + y^(2) - 4 y - 5 = 0 from the point (4, 5).

The nearest point on the circle x^(2)+y^(2)-6x+4y-12=0" from "(-5,4)" is "

STATEMENT -1 : The farthest point on the circle x^(2) + y^(2) - 2x - 4y + 4 from (0, 0) is (1, 3). and STATEMENT-2 : The farthest and nearest points on a circle from a given point are the end points of the diameter through the point.

STATEMENT -1 : The farthest point on the circle x^(2) + y^(2) - 2x - 4y + 4 from (0, 0) is (1, 3). and STATEMENT-2 : The farthest and nearest points on a circle from a given point are the end points of the diameter through the point.

The length of the tangent drawn to the circle x^(2)+y^(2)-2x+4y-11=0 from the point (1,3) is

The ltngth of the tangtnt drawn to the circle x^(2)+y^(2)-2 x+4 y-11=0 from the point (1,3) is

Find the co-ordinate of the point on the circle x^2+y^2-12x-4y +30=0 , which is farthest from the origin.