If the volume of two soap bubbles are V and 8V bubbles is

If the volumes of two soap bubbles are V and 8V then ratio of the excess pressures inside those bubbles is

The pressure inside two soap bubbles are 1.05 atm and 1.07 atmosphere. The volume of two bubbles are in the ratio of

The execc pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is

The excess pressure in soap bubble is 10(N)/(m^(2)) if eight soap bubble are combined to form a big soap bubble excess pressure in big bubble is (in (N)/(m^(2)))

The value V in the bent tube is initailly kept closed. Two soap bubbles A(smaller ) and B (larger )are formed at 2 open ends of the tube. V is now opened .and air can flow freely between the bubbles

In air, a charged soap bubble of radius 'R' breaks into 27 small soap bubbles of equal radius 'r '. Then the ratio of mechanical force acting per unit area of big soap bubble to that of a small soap bubble is

Tow soap bubbles A and B are formed at the two open ends of a tube. The bubble A is smaller then bubble B. If the valve on the tube connecting the two bubbles is opened and air can flow freely between the bubbles, then