The energy density of air medium is `44.25 xx 10^(-8) J//m^(3)`. The intensity of the electric field in the medium is

The energy density of air medium is 44.25xx10^(-8)J//m^(3) . The intensity of the electric field in the medium is

The energy density at a point in vacuum is 1.77xx10^(-7)J//m^(3) . The intensity of the electric field at the point is

If the velocity of light in a medium is 2.25 xx 10^(8) ms^(-1) then the refractive index of the medium will be

The energy density in a parallel plate capacitor is given as 2.1 × 10–9 J/m3. The value of the electric field in the region between the plates is :

The energy density at a point in a medium of dielectric constant 6 is 26.55xx10^(6)J//m^(3) . What is the electric field intensity at that point ? [epsi_(0)=8.85xx10^(-12)SI units]

Calculate the energy per unit volume of a medium of dielectric constant 3, if the intensity of the electric field is 100V//m .

The force experienced by a charge of 2mu C in an electric field is 3 xx 10^(-3)N . The intensity of the electric field.

The velocity of light in a medium is 2 xx 10^(8) m//s .What is the refractive index of the medium with respect to air, if the velocity of light in air is 3 xx 10^(8) m//s ?