If `(x^2+2x+7)/(2x+3)<6`, x`in` R then

0lt(2x-5)/2lt7, x in R

If x/4 lt (5x-2)/3 -(7x-3)/5, x in R then

If for x in R, (1)/(3) lt (x^(2) - 2x + 4)/(x^(2) + 2x + 4) lt 3 , then (9.3^(2x) + 6.3^(x) + 4)/(9.3^(2x) - 6.3^(x) + 4) lies between

If (y^(2)-6y+3)(x^(2)+x+1)lt2x AA x in R, then sum of all integral values of y is

x/4+(2-5x)/3lt(3-7x)/5, x in R

Solve and graph the solution set of : x + 5 ge 4(x - 1) and 3 - 2x lt - 7, x in R .