The energy density per unit volume of medium in an electric field of intensity `400 V//m` is (dielectric constant of material is 2 and `epsi_(0) = 8.85 xx10^(-12) `units)

The energy density in an electric field of intensity 100 V/m is

The energy density in an electric field of intensity 200 "volt"//m , if K=4 and epsi_(0)=8.85 xx 10^(-12) C^(2)//Nm^(2) is

A cube of marble having each side 1 cm is kept in an electric field of intensity 300 V/m. Determine the energy contained in the cube of dielectric constant 8. [Given : epsilon_(0) =8.85 xx 10^(-12) C^(2)//Nm^(2) ]

Calculate the energy per unit volume of a medium of dielectric constant 3, if the intensity of the electric field is 100V//m .

The energy per unit volume of a dielectric medium is directly proportional to square of

The energy density at a point in a medium of dielectric constant 6 is 26.55xx10^(6)J//m^(3) . What is the electric field intensity at that point ? [epsi_(0)=8.85xx10^(-12)SI units]

The parallel plate of a capacitor have an area 0.2 m^(2) and are 10^(-2) m apart. The original potential difference between them is 3000V, and it decreases to 1000 when a sheet of dielectric is inserted between the plates. Compute (a) Original capacitance C_(0) (b) The original charge Q on each plate . (C) Capacitance C after insertion of the dielectric . (d) Dielectric constant K . (e) The original field E_(0) between the plates and . (f) The electric field E_(0) between the plates and . (f) The electric field E after insertion of the dielectric . (epsi_(0) = 8.85 xx 10^(-12) S.I unit).

The electric field intensity at a point near a sphere of radius r and surface density of rho in a medium of dielectric constant K is